Q. Fundamental frequency of an open pipe of length $0.5\ m$ is equal to the frequency of the first overtone of a closed pipe of length $l.$ The value of $l_{c}$ is $(m)$
A) 1.5
B) 0.75
C) 2
D) 1
Explanation
(b) First tone of open pipe = first overtone of closed pipe
$\Rightarrow \frac{v}{2l_{0}} = \frac{3v}{4l_{c}} \Rightarrow l_{c} = \frac{3 \times 2 \times 0.5}{4} = 0.75m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.