Q. Find the fundamental frequency of a closed pipe, if the length of the air column is $42\ m.$ (speed of sound in air $= 332\ m/sec$)
A) $2\ Hz$
B) $4\ Hz$
C) $7\ Hz$
D) $9\ Hz$
Explanation
(a) For closed pipe $n = \frac{v}{4l} \Rightarrow n = \frac{332}{4 \times 42} = 2Hz$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.