Q. In Melde’s experiment, the string vibrates in 4 loops when a 50 g weight is placed in the pan of weight 15 g. To made the string vibrate in 6 loops, the weight that has to be removed from the pan in approximately

A) 7 g
B) 36 g
C) 21 g
D) 29 g
Explanation

(b) As $p\sqrt{T} = constant\ \therefore\ \ \frac{T_{2}}{T_{1}} = \frac{p_{1}^{2}}{p_{2}^{2}} = \frac{4^{2}}{6^{2}}$
$T_{2} = \frac{16}{36}T_{1} = \frac{16}{36} \times 65 = 29$
$\therefore$ Weight to be removed $= 65 - 29 = 36$ g

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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