Q.
If the speed of a wave doubles as it passes from shallow water deeper water, its wavelength will be
A) Unchanged
B) Halved
C) Doubled
D) Quadrupled
Explanation
(c) Since frequency remains unchanged
V=v’
$\frac{v}{\lambda} = \frac{v^{'}}{\lambda^{'}}$
$\frac{v}{\lambda} = \frac{2v}{\lambda^{'}}$
$\lambda^{'} = \frac{2v}{v}\lambda$
$\lambda^{'} = 2\lambda$
Hence, its wavelength will become twice.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.