Q. An air capacitor of capacity $C = 10\mu F$ is connected to a constant voltage battery of $12\ V.$ Now the space between the plates is filled with a liquid of dielectric constant 5. The charge that flows now from battery to the capacitor is
A) $120\mu C$
B) $699\mu C$
C) $480\mu C$
D) $24\mu C$
Explanation
(c) Initially charge on the capacitor $Q = 10 \times 12 = 120\mu C$
Finally charge on the capacitor $Q^{'} = (5 \times 10) \times 12 = 600\mu C$
So charge supplied by the battery later $= Q^{'} - Q = 480\mu C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.