Q. The force of interaction between two charges $q_{1} = 6\mu\ $C and $q_{2} = 2\mu$C is 12 N. If charge $q = - 2\mu$C is added to each of the charges, then the new force of interaction is
A) $2 \times 10^{- 7}$ N
B) Zero
C) 30 N
D) $2 \times 10^{- 3}$ N
Explanation
(b) New force $F = \frac{1}{4\pi\varepsilon_{0}}\frac{(6 - 2)(2 - 2)}{r^{2}} \times 10^{- 12} = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.