Q.
Two dielectric slabs of constant $K_{1}$ and $K_{2}$ have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor
A) $\frac{2\varepsilon_{0}A}{d}(K_{1} + K_{2})$
B) $\frac{2\varepsilon_{0}A}{d}\left( \frac{K_{1} + K_{2}}{K_{1} \times K_{2}} \right)$
C) $\frac{2\varepsilon_{0}A}{2}\left( \frac{K_{1} \times K_{2}}{K_{1} + K_{2}} \right)$
D) $\frac{2\varepsilon_{0}A}{d}\left( \frac{K_{1} \times K_{2}}{K_{1} + K_{2}} \right)$
Explanation
(d) The two capacitors formed by the slabs may assumed to be in series combination
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.