Q.
Four condenser each of capacity $4\mu F$ are connected as shown in figure. $V_{P} - V_{Q} = 15\ volts.$ The energy stored in the system is
A) $2400\ ergs$
B) $1800\ ergs$
C) $3600\ ergs$
D) $5400\ ergs$
Explanation
(b) Total capacitance of given system $C_{eq} = \frac{8}{5}\mu F$
$U = \frac{1}{2}C_{eq}V^{2} = \frac{1}{2} \times \frac{8}{5} \times 10^{- 6} \times 225 = 180 \times 10^{- 6}\ J$
$= 180 \times 10^{- 6} \times 10^{7}erg = 1800\ erg$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.