Q. For a dipole $q = 2 \times 10^{- 6}C$ and $d = 0.01\ m.$ Calculate the maximum torque for this dipole if $E = 5 \times 10^{5}\ N/C$
A) $1 \times 10^{- 3}Nm^{- 1}$
B) $10 \times 10^{- 3}Nm^{- 1}$
C) $10 \times 10^{- 3}Nm$
D) $1 \times 10^{2}Nm^{2}$
Explanation
(c) $\tau_{\max} = pE = q(2l)E = 2 \times 10^{- 6} \times 0.01 \times 5 \times 10^{5}$
$= 10 \times 10^{- 3}N - m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.