Q. When a charge of 3 $coulomb$ is placed in a uniform electric field, it experiences a force of 3000 $Newton.$ Within this field, potential difference between two points separated by a distance of 1$cm$ is
A) $10\ volts$
B) $90\ volts$
C) $1000\ volts$
D) $3000\ volts$
Explanation
(a) $V = Ed = \frac{3000}{3} \times 10^{- 2} = 10V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.