Q.
In the following figure, the charge on each condenser in the steady state will be
A) $3\ \mu C$
B) $6\ \mu C$
C) $9\ \mu C$
D) $12\ \mu C$
Explanation
(d) In steady state current flows through $4\Omega$ resistance only and it is $i = \frac{10}{(4 + 1)} = 2amp.$ Potential difference across $4\Omega$ resistance is $V = 2 \times 4 = 8\ volt$
Hence, potential difference across each capacitor is $4V$
So charge on each capacitor $Q = 3 \times 4 = 12\mu C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.