Q. Two spherical conductors each of capacity $C$ are charged to potentials $V$ and $- V.$ These are then connected by means of a fine wire. The loss of energy will be
A) Zero
B) $\frac{1}{2}CV^{2}$
C) $CV^{2}$
D) $2CV^{2}$
Explanation
(c) $\mathrm{\Delta}V = \frac{1}{2}\frac{C \times C}{(C + C)}\left| V - ( - V) \right|^{2} = CV^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.