(a) We have $C = \frac{\varepsilon_{0}A}{d} \Rightarrow A = \frac{Cd}{\varepsilon_{0}} = \frac{3 \times 5 \times 10^{- 3}}{8.85 \times 10^{- 12}}$ $= 1.69 \times 10^{9}m^{2}$
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