Q. A capacitor of $20\mu F$ is charged to $500\ volts$ and connected in parallel with another capacitor of $10\mu F$ and charged to $200\ volts.$ The common potential is
A) $200\ volts$
B) $300\ volts$
C) $400\ volts$
D) $500\ volts$
Explanation
(c) $V = \frac{V_{1}C_{1} + V_{2}C_{2}}{C_{1} + C_{2}} = \frac{500 \times 20 + 200 \times 10}{20 + 10} = 400V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.