Q. A charge q is placed at the corner of a cube of side$a$. The electric flux through the cube is
A) $\frac{q}{\varepsilon_{0}}$
B) $\frac{q}{3\varepsilon_{0}}$
C) $\frac{q}{6\varepsilon_{0}}$
D) $\frac{q}{8\varepsilon_{0}}$
Explanation
(d) If charge q is placed at a corner of cube, it will be divided into 8 such cubes. Therefore, electric flux through the cube is
$\phi^{'} = \frac{1}{8}\left( \frac{q}{\varepsilon_{0}} \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.