Q.
In the circuit shown in the figure, the potential difference across the $4.5\mu F$ capacitor is
A) $\frac{8}{3}volts$
B) $4\ volts$
C) $6\ volts$
D) $8\ volts$
Explanation
(d) The given circuit can be redrawn as follows potential difference across $4.5\ \mu F$ capacitor
[image:1_image246.emf]
$V = \frac{9}{\left( \frac{9}{2} + 9 \right)} \times 12$
$= 8\ V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.