Q. The electric flux for Gaussian surface $A$ that enclose the charged particles in free space is (given $q_{1} = - 14\ nC,\ q_{2} = 78.85\ nC,\ q_{3} = - 56\ nC$)
A) $10^{3}Nm^{2}C^{- 1}$
B) $10^{3}CN^{- 1}m^{- 2}$
C) $6.32 \times 10^{3}Nm^{2}C^{- 1}$
D) $6.32 \times 10^{3}CN^{- 1}m^{- 2}$
Explanation
(a) Flux is due to charges enclosed per $\varepsilon_{0}$
$\therefore$ Total flux $= ( - 14 + 78.85 - 56)nC/\varepsilon_{0}$
$= 8.85 \times 10^{- 9}C \times \frac{4\pi}{4\pi\varepsilon_{0}} = 8.85 \times 10^{- 9} \times 9 \times 10^{9} \times 4\pi$
$= 1000.4\ Nm^{2}/C\ \ i.\ e.\ 1000\ Nm^{2}C^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.