Q. The energy required to charge a capacitor of $5\mu F$ by connecting a $d.c.$ source of $20kV$ is

A) $10\ kJ$
B) $5\ kJ$
C) $2\ kJ$
D) $1\ kJ$
Explanation

(d) $U = \frac{1}{2}CV^{2} = \frac{1}{2}5 \times 10^{- 6} \times \left( 20 \times 10^{3} \right)^{2} = 1kJ$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.