Q.
In the figure, three capacitors each of capacitance $6\ pF$ are connected in series. The total capacitance of the combination will be
A) $9 \times 10^{- 12}F$
B) $6 \times 10^{- 12}F$
C) $3 \times 10^{- 12}F$
D) $2 \times 10^{- 12}F$
Explanation
(d) $C^{'} = C/n = \frac{6 \times 10^{- 12}}{3} = 2 \times 10^{- 12}F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.