Q. Three capacitors of capacitance $3\ \mu\ F$ are connected in a circuit. Then their maximum and minimum capacitance will be
A) $9\ \mu\ F,\ 1\ \mu\ F$
B) $8\ \mu\ F,2\ \mu\ F$
C) $9\ \mu\ F,0\ \mu\ F$
D) $3\ \mu\ F,2\ \mu\ F$
Explanation
(a) $C_{\max} = nC = 3 \times 3 = 9\mu F$
$C_{\min} = \frac{C}{n} = \frac{3}{3} = 1\ \mu F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.