Q. Two particle of equal mass $m$ and charge $q$ are placed at a distance of $16\ cm.$ They do not experience any force. The value of $\frac{q}{m}$ is
A) $l$
B) $\sqrt{\frac{\pi\varepsilon_{0}}{G}}$
C) $\sqrt{\frac{G}{4\pi\varepsilon_{0}}}$
D) $\sqrt{4\pi\varepsilon_{0}G}$
Explanation
(d) They will not experience any force if $\left| \overrightarrow{F_{G}} \right| = \left| \overrightarrow{F_{e}} \right|$
$\Rightarrow G\frac{m^{2}}{\left( 16 \times 10^{- 2} \right)^{2}} = \frac{1}{4\pi\varepsilon_{0}}.\ \frac{q^{2}}{\left( 16 \times 10^{- 2} \right)^{2}} \Rightarrow \frac{q}{m} = \sqrt{4\pi\varepsilon_{0}G}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.