Q.
The total energy stored in the condenser system shown in the figure will be
A) $8\ \mu\ J$
B) $16\ \mu\ J$
C) $2\ \mu\ J$
D) $4\ \mu\ J$
Explanation
(a) $3\mu F$ and $6\mu F$ are series; $\therefore\frac{3 \times 6}{(3 + 6)} = 2\mu F$
This is in parallel with $2\mu F$
Total capacitance in the circuit is $4\mu F$
$\therefore U = (1/2)V^{2}C = (1/2) \times 2^{2} \times 4 \times 10^{- 6}J = 8\mu J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.