(b) There are two capacitors parallel to each other
$\therefore$ Total capacitance $= \frac{2\varepsilon_{0}A}{d}$
$\therefore$ Energy stored $= \frac{1}{2}\left( \frac{2\varepsilon_{0}A}{d} \right)V^{2}$
$= \frac{8.86 \times 10^{- 12} \times 50 \times 10^{- 4} \times 12^{2}}{3 \times 10^{- 3}} = 2.1 \times 10^{- 9}\ J$