Q.
The equivalent capacitance between $A$ and $B$ in the figure is $1\mu F.$ Then the value of capacitance $C$ is
A) $1.4\mu F$
B) $2.5\mu F$
C) $3.5\mu F$
D) $1.2\mu F$
Explanation
(a) From the given figure, total capacitance is
$\frac{1}{1} = \frac{1}{C} + \frac{1}{(1 + 2.5)} \Rightarrow 1 = \frac{1}{C} + \frac{1}{3.5} \Rightarrow C = \frac{3.5}{2.5} = 1.4\ \mu F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.