Q. The work done in bringing a $20\ coulomb$ charge from point $A$ to point $B$ for distance $0.2m$ is $2j.$ The potential difference between the two points will be (in $volt$)
A) 0.2
B) 8
C) 0.1
D) 0.4
Explanation
(c) By using $W = Q.\mathrm{\Delta}V \Rightarrow \mathrm{\Delta}V = \frac{2}{20} = 0.1\ volt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.