Q.
Two parallel plate of area $A$ are separated by two different dielectrics as shown in figure. The net capacitance is
A) $\frac{4\varepsilon_{0}A}{3d}$
B) $\frac{3\varepsilon_{0}A}{4d}$
C) $\frac{2\varepsilon_{0}A}{d}$
D) $\frac{\varepsilon_{0}A}{d}$
Explanation
(a) Parallel plate capacitor
$C = K\varepsilon_{0}A/d$
As given in fig., for series combination
$\frac{1}{C'} = \frac{1}{\frac{\varepsilon_{0}A}{\frac{d}{2}}} + \frac{1}{\frac{2\varepsilon_{0}A}{\frac{d}{2}}} \Rightarrow C = \frac{4}{3}\frac{\varepsilon_{0}A}{d}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.