Q. What is angle between electric field and equipotential surface?
A) $90{^\circ}$always
B) $0{^\circ}$ always
C) $0{^\circ}\ to\ 90{^\circ}$
D) $0{^\circ}\ to\ 180{^\circ}$
Explanation
(a) Potential gradient along equipotential surface is zero.
i.e., $E\cos{\theta = - \frac{dV}{dr} = 0}$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \theta = 90{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.