Q. The Value (in vacuum) of energy density at a place in a region of electric field intensity $E,$ due to it, is given by
A) $\frac{\varepsilon_{0}E^{2}}{2}$
B) $\frac{\varepsilon_{0}E}{2}$
C) $\frac{E^{2}}{2\varepsilon_{0}}$
D) $\frac{E\varepsilon_{0}^{2}}{2}$
Explanation
The correct answer is Option A: $\frac{\varepsilon_{0}E^{2}}{2}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.