Q. 64 drops of mercury each charged to a potential of $10V.$ They are combined to form one bigger drop. The potential of this drop will be (Assume all the drops to be spherical)
A) $160\ V$
B) $80\ V$
C) $10\ V$
D) $640\ V$
Explanation
(a) $V = n^{2/3}v = (64)^{2/3} \times 10 = 160\ volt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.