Q. Two condensers of capacity $0.3\mu F$ and $0.6\mu F$ respectively are connected in series. The combination is connected across a potential of $6\ volts.$ The ratio of energies stored by the condensers will be
A) $\frac{1}{2}$
B) 2
C) $\frac{1}{4}$
D) 4
Explanation
(b) In series combination $Q$ is constant, hence according to
$U = \frac{Q^{2}}{2C} \Rightarrow U \propto \frac{1}{C} \Rightarrow \frac{U_{1}}{U_{2}} = \frac{C_{2}}{C_{1}} = \frac{0.6}{0.3} = \frac{2}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.