Q. Two electric charges $12\mu C\ and - 6\mu C$ are placed $20\ cm$ apart in air. There will be a point $P$ on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of $P$ from $- 6\mu C$ charge is

A) $0.10\ m$
B) $0.15\ m$
C) $0.20\ m$
D) $0.25\ m$
Explanation

(c) Point $P$ will lie near the charge which is smaller in magnitude $i.e. - 6\mu C$. Hence potential at $P$
$V = \frac{1}{4\pi\varepsilon_{0}}\frac{\left( - 6 \times 10^{- 6} \right)}{x} + \frac{1}{4\pi\varepsilon_{0}}\frac{(12 \times 10^{- 6})}{(0.2 + x)} = 0 \Rightarrow x = 0.2\ m$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.