(b) Force on electron $F = QE = Q\left( \frac{V}{d} \right)$ $\Rightarrow F = \left( 1.6 \times 10^{- 19} \right)\left( \frac{1000}{2 \times 10^{- 3}} \right) = 8 \times 10^{- 14}N$
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