Q. A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of $1\ kV,$ its kinetic energy will be
A) $1840\ keV$
B) $1/1840\ keV$
C) $1\ keV$
D) $920\ keV$
Explanation
(c) $KE = QV = e \times 10^{3}V = 1KeV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.