Q. The magnitude of electric field intensity $E$ is such that, an electron placed in it would experience an electrical force equal to its weight is given by
A) $mge$
B) $\frac{mg}{e}$
C) $\frac{e}{mg}$
D) $\frac{e^{2}}{m^{2}}g$
Explanation
(b) According to the question, $eE = mg \Rightarrow E = \frac{mg}{e}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.