Q. A particle of mass $m$ carrying charge $q$ is kept at rest in a uniform electric field $E$ and then released. The kinetic energy gained by the particle, when it moves through a distance $y$ is
A) $\frac{1}{2}qEy^{2}$
B) $qEy$
C) $qEy^{2}$
D) $qE^{2}y$
Explanation
(b) Kinetic energy =work done
$= F.d$
$= qE \times y$
$= qEy$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.