Q. Two small spherical balls each carrying a charge $Q = 10\mu C\ (10\ micro - coulomb)$ are suspended by two insulating threads of equal lengths $1m$ each, from a point fixed in the ceiling. It is found that in equilibrium threads are separated by an angle $60^{o}$ between them, as shown in the figure. What is the tension in the threads (Given $:\frac{1}{\left( 4\pi\varepsilon_{0} \right)} = 9 \times 10^{9}Nm/C^{2})$

A) $18\ N$
B) $1.8\ N$
C) $0.18\ N$
D) None of the above
Explanation

(b) In the following figure, in equilibrium $F_{e} = T\sin 30^{o},\ r = 1m$
[image:1_image276.emf]
$\Rightarrow 9 \times 10^{9}.\frac{Q^{2}}{r^{2}} = T \times \frac{1}{2}$
$\Rightarrow 9 \times 10^{9}.\frac{\left( 10 \times 10^{- 6} \right)^{2}}{1^{2}} = T \times \frac{1}{2}\ \Rightarrow T = 1.8\ N$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.