Q. If the electric flux entering and leaving an enclosed surface respectively is $\phi_{1}$ and $\phi_{2}$ the electric charge inside the surface will be
A) $\left( \phi_{1} + \phi_{2} \right)\varepsilon_{0}$
B) $\left( \phi_{2} - \phi_{1} \right)\varepsilon_{0}$
C) $\left( \phi_{1} + \phi_{2} \right)/\varepsilon_{0}$
D) $\left( \phi_{2} - \phi_{1} \right)/\varepsilon_{0}$
Explanation
(b) $\phi_{net} = \frac{1}{\varepsilon_{0}} \times Q_{enc} \Rightarrow Q_{enc} = \left( \phi_{2} - \phi_{1} \right)\varepsilon_{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.