Q. To obtain $3\mu F$ capacity from three capacitors of $2\mu F$ each, they will be arranged
A) All the three in series
B) All the three in parallel
C) Two capacitors in series and the third in parallel with the combination of first two
D) Two capacitors in parallel and the third in series with the combination of first two
Explanation
(c) $C = \frac{2 \times 2}{2 + 2} + 2 = 3\ \mu F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.