Q. When a proton is accelerated through $1V,$ then its kinetic energy will be
A) $1840\ eV$
B) $13.6\ eV$
C) $1\ eV$
D) $0.54\ eV$
Explanation
(c) $\mathrm{\Delta}KE = qV = eV = e \times 1V = 1eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.