Four point $+ ve$ charges of same magnitude $(Q)$ are placed at four corners of a rigid square frame as shown in figure. The plane of the frame is perpendicular to $Z -$axis. If $a - ve$ point charge is placed at a distance $z$ away from the above frame $(z

Question

Four point $+ ve$ charges of same magnitude $(Q)$ are placed at four corners of a rigid square frame as shown in figure. The plane of the frame is perpendicular to $Z -$axis. If $a - ve$ point charge is placed at a distance $z$ away from the above frame $(z < < L)$ then [image:1_image75.emf]

Dr. Abubacker · Accepted Answer

(a) The negative charge oscillates, the resultant force acts as a restoring force and proportional to displacement. When it reaches the plane $XY,$ the resultant force is zero and the mass moves down due to inertia. Thus oscillation is set

Q. Four point $+ ve$ charges of same magnitude $(Q)$ are placed at four corners of a rigid square frame as shown in figure. The plane of the frame is perpendicular to $Z -$axis. If $a - ve$ point charge is placed at a distance $z$ away from the above frame $(z < < L)$ then

Explanation

Reviewed by Dr. Abubacker

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