Q. A uniform electric field having a magnitude $E_{0}$ and direction along the positive $X - axis$ exists. If the potential $V$ is zero as $x = 0,$ then its value at $X = + x$ will be
A) $V_{(x)} = \ + x\ E_{0}$
B) $V_{x} = - xE_{0}$
C) $V_{x} = + x^{2}E_{0}$
D) $V_{x} = - x^{2}E_{0}$
Explanation
(b) $\because E = - \frac{dV}{dX} \Rightarrow V_{x} = - xE_{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.