(c) [image:1_image279.wmf]Length of each side of square is $\sqrt{2}m$ so distance of it’s centre from each corner is $\frac{\sqrt{2}}{\sqrt{2}} = 1m$
Potential at the centre
$V = 9 \times 10^{9}\left\lbrack \frac{10 \times 10^{-}6}{1} + \frac{5 \times 10^{- 6}}{1} - \frac{3 \times 10^{- 6}}{1} + \frac{8 \times 10^{- 6}}{1} \right\rbrack$
$= 1.8 \times 10^{5}\ V$