Q. Eight small drops, each of radius $r$ and having same charge $q$ are combined to form a big drop. The ratio between the potentials of the bigger drop and the smaller drop is
A) 8 : 1
B) 4 : 1
C) 2 : 1
D) 1 : 8
Explanation
(b) By using $V_{big} = n^{2/3}v_{small} \Rightarrow \frac{V_{Big}}{v_{small}} = (8)^{2/3} = \frac{4}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.