Q. Five point charge each having magnitude $''q''$ are placed at the corner of hexagon as shown in fig. Net electric field at the centre $''O''$ is $\overrightarrow{E}.$ To get net electric field at $''O''$ be $6\overrightarrow{E},$ charge placed on the remaining sixth corner should be

A) $6\ q$
B) $- 6\ q$
C) $5\ q$
D) $- 5\ q$
Explanation

(d) To obtained net field $6E$ at centre $O,$ the charge to be placed at remaining sixth corner is $- 5q.$ (see following figure)
[image:1_image280.emf]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.