There is a uniform electric field of strength $10^{3}V/m$ along $y$-axis. A body of mass $1g$ and charge $10^{- 6}C$ is projected into the field from origin along the positive $x$-axis with a velocity $10m/s.$ Its speed in $m/s$ after $10s$ is (Neglect gravitation)

Question

Dr. Abubacker · Accepted Answer

(c) Body moves along the parabolic path
For vertical motion : By using $v = u + at$
$\Rightarrow v_{y} = 0 + \frac{QE}{m}.t = \frac{10^{- 6} 	imes 10^{3}}{10^{- 3}} 	imes 10 = 10m/\sec$
For horizontal motion – It’s horizontal velocity remains the same $i.e.$ after $10\ sec,$ horizontal velocity of body $v_{x} = 10m/sec$
Velocity after $10\sec{v = \sqrt{v_{x}^{2} + v_{y}^{2} = 10\sqrt{2}}\ m/sec}$

Q. There is a uniform electric field of strength $10^{3}V/m$ along $y$-axis. A body of mass $1g$ and charge $10^{- 6}C$ is projected into the field from origin along the positive $x$-axis with a velocity $10m/s.$ Its speed in $m/s$ after $10s$ is (Neglect gravitation)

Explanation

Reviewed by Dr. Abubacker

Want more practice?