(d) Potential due to dipole in general position is given by
$V = \frac{k.p\cos\theta}{r^{2}} \Rightarrow V = \frac{k.p\cos\theta r}{r^{3}} = \frac{k.(\overrightarrow{p}.\overrightarrow{r})}{r^{3}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.