Q. The capacities and connection of five capacitors are shown in the adjoining figure. The potential difference between the points $A$ and $B$ is $60\ volts.$ Then the equivalent capacity between $A$ and $B$ and the charge on $5\mu F$ capacitance will be respectively
A) $44\mu F;300\mu C$
B) $16\mu F;150\mu C$
C) $15\mu F;200\mu C$
D) $4\mu F;50\mu C$
Explanation
(d) The given circuit can be redrawn as follows
Equivalent capacitance of the circuit $C_{AB} = 4\mu F$
Charge given by the battery $Q = C_{eq}V = 4 \times 60 = 240\mu C$
Charge in $5\mu F$ capacitor $Q^{'} = \frac{5}{(10 + 5 + 9)} \times 240 = 50\mu C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.