Q.
Three charges are placed at the vertices of an equilateral triangle of side $''a''$ as shown in the following figure. The force experienced by the charge placed at the vertex $A$ in a direction normal to $BC$ is
A) $Q^{2}/(4\pi\varepsilon_{0}a^{2})$
B) $- Q^{2}/(4\pi\varepsilon_{0}a^{2})$
C) Zero
D) $Q^{2}/(2\pi\varepsilon_{0}a^{2})$
Explanation
(c) $\left| \overrightarrow{F_{B}} \right| = \left| \overrightarrow{F_{C}} \right| = k.\frac{Q^{2}}{a^{2}}$
[image:1_image291.emf]
Hence force experienced by the charge at $A$ in the direction normal to $BC$ is zero
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.