(a) By using $U = 9 \times 10^{9}\frac{Q_{1}Q_{2}}{r}$ $\Rightarrow U = 9 \times 10^{9} \times \frac{10^{- 6} \times 10^{- 6}}{1} = 9 \times 10^{- 3}\ J$
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Ph.D. in Physics with 19+ years of teaching experience.