Q. The ratio of electric field and potential $(E/V)$ at midpoint of electric dipole, for which separation is $l$
A) $\frac{1}{l}$
B) $l$
C) $\frac{2}{l}$
D) None of these
Explanation
(d) Electric field at $''O^{''}E = \frac{2kq}{l^{2}}$
[image:1_image292.emf]
Potential at $''O''$
$V = 0$
$\therefore E/V = \infty$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.